String Interpolation with Data Support

The strs_format function provides string interpolation using values from a data argument, similar to Python's str.format method. For more information, see the details.

Usage

strs_format(string, ..., .data = NULL)

Arguments

string: A character vector containing the string with placeholders in curly braces {}. If the vector contains more than one string, they are concatenated before interpolation.
...: Named arguments that will be made available during string interpolation. Note that these will take precedence over values in .data.
.data: List-like (e.g., data.frame, list, environment, etc.) object that will be used for lookups during string interpolation.

Value

A character vector with the placeholders replaced by the evaluated expressions.

Details

Under the hood, this function uses the glue::glue_data() function to perform the interpolation. By default, this function will only use the variables provided in ... and .data. It will NOT use the immediate environment to perform the interpolations. If any interpolated expression is NA, it will be NA in the output. If any interpolated expression is NULL, it will be NULL in the output.

Examples

# Using a named list for substitutions
data_list <- list(name = "Alice", age = 30)
strs_format("My name is {name} and I am {age} years old.", .data = data_list)
#> [1] "My name is Alice and I am 30 years old."
# Output: "My name is Alice and I am 30 years old."

# Using additional arguments
strs_format("My name is {name} and I am {age} years old.", name = "Bob", age = 25)
#> [1] "My name is Bob and I am 25 years old."
# Output: "My name is Bob and I am 25 years old."